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2022-08-19 20:08

您好,兩種都可以,主要是數(shù)學(xué)式子的變換:(F/P,9%,4)→F=P*(1+9%)^4→F/P=(1+9%)^4,(F/P,9%,5)→F=P*(1+9%)^5→F/P=(1+9%)^5,(F/A,9%,4)→F=A+A*(1+9%)+A(1+9%)^2+A(1+9%)^3→F/A={1+(1+9%)+(1+9%)^2+(1+9%)^3},所以(F/A,9%,5)→F=A+A*(1+9%)+A(1+9%)^2+A(1+9%)^3+A(1+9%)^4→F/A={1+(1+9%)+(1+9%)^2+(1+9%)^3+(1+9%)^4},(F/A,9%,,5)=(F/A,9%,4)+(F/P,9%,4)所以書上是對的,(F/A,9%,5)={1+(1+9%)+(1+9%)^2+(1+9%)^3}*(1+9%)+1=(F/A,9%,4)*(1+9%)+1所以題庫解題思路也是對的。

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相關(guān)問題討論
您好,兩種都可以,主要是數(shù)學(xué)式子的變換:(F/P,9%,4)→F=P*(1%2B9%)^4→F/P=(1%2B9%)^4,(F/P,9%,5)→F=P*(1%2B9%)^5→F/P=(1%2B9%)^5,(F/A,9%,4)→F=A%2BA*(1%2B9%)%2BA(1%2B9%)^2%2BA(1%2B9%)^3→F/A={1%2B(1%2B9%)%2B(1%2B9%)^2%2B(1%2B9%)^3},所以(F/A,9%,5)→F=A%2BA*(1%2B9%)%2BA(1%2B9%)^2%2BA(1%2B9%)^3%2BA(1%2B9%)^4→F/A={1%2B(1%2B9%)%2B(1%2B9%)^2%2B(1%2B9%)^3%2B(1%2B9%)^4},(F/A,9%,,5)=(F/A,9%,4)%2B(F/P,9%,4)所以書上是對的,(F/A,9%,5)={1%2B(1%2B9%)%2B(1%2B9%)^2%2B(1%2B9%)^3}*(1%2B9%)%2B1=(F/A,9%,4)*(1%2B9%)%2B1所以題庫解題思路也是對的。
2022-08-19 20:08:14
好的謝謝您
2022-03-30 10:25:30
你好這個實務(wù)中是可以的,你可以按不一樣的,就別登記錯就可以了
2021-06-24 09:26:38
你好! 是的,都是對的,你的理解很對
2021-05-16 13:25:28
你好,第二種方式核算,第一種方式實際抵扣67500 第二種方式實際抵扣70200
2020-07-09 13:32:31
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